(5b+1)(b-12)=0

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Solution for (5b+1)(b-12)=0 equation:


Simplifying
(5b + 1)(b + -12) = 0

Reorder the terms:
(1 + 5b)(b + -12) = 0

Reorder the terms:
(1 + 5b)(-12 + b) = 0

Multiply (1 + 5b) * (-12 + b)
(1(-12 + b) + 5b * (-12 + b)) = 0
((-12 * 1 + b * 1) + 5b * (-12 + b)) = 0
((-12 + 1b) + 5b * (-12 + b)) = 0
(-12 + 1b + (-12 * 5b + b * 5b)) = 0
(-12 + 1b + (-60b + 5b2)) = 0

Combine like terms: 1b + -60b = -59b
(-12 + -59b + 5b2) = 0

Solving
-12 + -59b + 5b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-1 + -5b)(12 + -1b) = 0

Subproblem 1

Set the factor '(-1 + -5b)' equal to zero and attempt to solve: Simplifying -1 + -5b = 0 Solving -1 + -5b = 0 Move all terms containing b to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -5b = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -5b = 0 + 1 -5b = 0 + 1 Combine like terms: 0 + 1 = 1 -5b = 1 Divide each side by '-5'. b = -0.2 Simplifying b = -0.2

Subproblem 2

Set the factor '(12 + -1b)' equal to zero and attempt to solve: Simplifying 12 + -1b = 0 Solving 12 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + -1b = 0 + -12 Combine like terms: 12 + -12 = 0 0 + -1b = 0 + -12 -1b = 0 + -12 Combine like terms: 0 + -12 = -12 -1b = -12 Divide each side by '-1'. b = 12 Simplifying b = 12

Solution

b = {-0.2, 12}

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