(5b+2)(b+2)=0

Solution for (5b+2)(b+2)=0 equation:

Simplifying
(5b + 2)(b + 2) = 0

Reorder the terms:
(2 + 5b)(b + 2) = 0

Reorder the terms:
(2 + 5b)(2 + b) = 0

Multiply (2 + 5b) * (2 + b)
(2(2 + b) + 5b * (2 + b)) = 0
((2 * 2 + b * 2) + 5b * (2 + b)) = 0
((4 + 2b) + 5b * (2 + b)) = 0
(4 + 2b + (2 * 5b + b * 5b)) = 0
(4 + 2b + (10b + 5b2)) = 0

Combine like terms: 2b + 10b = 12b
(4 + 12b + 5b2) = 0

Solving
4 + 12b + 5b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(2 + b)(2 + 5b) = 0

Subproblem 1
Set the factor '(2 + b)' equal to zero and attempt to solve:

Simplifying
2 + b = 0

Solving
2 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + b = 0 + -2
b = 0 + -2

Combine like terms: 0 + -2 = -2
b = -2

Simplifying
b = -2
Subproblem 2
Set the factor '(2 + 5b)' equal to zero and attempt to solve:

Simplifying
2 + 5b = 0

Solving
2 + 5b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 5b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 5b = 0 + -2
5b = 0 + -2

Combine like terms: 0 + -2 = -2
5b = -2

Divide each side by '5'.
b = -0.4

Simplifying
b = -0.4
Solution
b = {-2, -0.4}