(5b-4)=(3b+7)

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Solution for (5b-4)=(3b+7) equation:



(5b-4)=(3b+7)
We move all terms to the left:
(5b-4)-((3b+7))=0
We get rid of parentheses
5b-((3b+7))-4=0
We calculate terms in parentheses: -((3b+7)), so:
(3b+7)
We get rid of parentheses
3b+7
Back to the equation:
-(3b+7)
We get rid of parentheses
5b-3b-7-4=0
We add all the numbers together, and all the variables
2b-11=0
We move all terms containing b to the left, all other terms to the right
2b=11
b=11/2
b=5+1/2

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