(5b-4c)(5b-2c)=

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Solution for (5b-4c)(5b-2c)= equation: 


Simplifying
(5b + -4c)(5b + -2c) = 0

Multiply (5b + -4c) * (5b + -2c)
(5b * (5b + -2c) + -4c * (5b + -2c)) = 0
((5b * 5b + -2c * 5b) + -4c * (5b + -2c)) = 0

Reorder the terms:
((-10bc + 25b2) + -4c * (5b + -2c)) = 0
((-10bc + 25b2) + -4c * (5b + -2c)) = 0
(-10bc + 25b2 + (5b * -4c + -2c * -4c)) = 0
(-10bc + 25b2 + (-20bc + 8c2)) = 0

Reorder the terms:
(-10bc + -20bc + 25b2 + 8c2) = 0

Combine like terms: -10bc + -20bc = -30bc
(-30bc + 25b2 + 8c2) = 0

Solving
-30bc + 25b2 + 8c2 = 0

Solving for variable 'b'.

Factor a trinomial.
(5b + -4c)(5b + -2c) = 0


Subproblem 1
Set the factor '(5b + -4c)' equal to zero and attempt to solve:

Simplifying
5b + -4c = 0

Solving
5b + -4c = 0

Move all terms containing b to the left, all other terms to the right.

Add '4c' to each side of the equation.
5b + -4c + 4c = 0 + 4c

Combine like terms: -4c + 4c = 0
5b + 0 = 0 + 4c
5b = 0 + 4c
Remove the zero:
5b = 4c

Divide each side by '5'.
b = 0.8c

Simplifying
b = 0.8c

Subproblem 2
Set the factor '(5b + -2c)' equal to zero and attempt to solve:

Simplifying
5b + -2c = 0

Solving
5b + -2c = 0

Move all terms containing b to the left, all other terms to the right.

Add '2c' to each side of the equation.
5b + -2c + 2c = 0 + 2c

Combine like terms: -2c + 2c = 0
5b + 0 = 0 + 2c
5b = 0 + 2c
Remove the zero:
5b = 2c

Divide each side by '5'.
b = 0.4c

Simplifying
b = 0.4c
Solution
b = {0.8c, 0.4c}

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