(5c+3)(c+9)=0

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Solution for (5c+3)(c+9)=0 equation:


Simplifying
(5c + 3)(c + 9) = 0

Reorder the terms:
(3 + 5c)(c + 9) = 0

Reorder the terms:
(3 + 5c)(9 + c) = 0

Multiply (3 + 5c) * (9 + c)
(3(9 + c) + 5c * (9 + c)) = 0
((9 * 3 + c * 3) + 5c * (9 + c)) = 0
((27 + 3c) + 5c * (9 + c)) = 0
(27 + 3c + (9 * 5c + c * 5c)) = 0
(27 + 3c + (45c + 5c2)) = 0

Combine like terms: 3c + 45c = 48c
(27 + 48c + 5c2) = 0

Solving
27 + 48c + 5c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(9 + c)(3 + 5c) = 0

Subproblem 1

Set the factor '(9 + c)' equal to zero and attempt to solve: Simplifying 9 + c = 0 Solving 9 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + c = 0 + -9 Combine like terms: 9 + -9 = 0 0 + c = 0 + -9 c = 0 + -9 Combine like terms: 0 + -9 = -9 c = -9 Simplifying c = -9

Subproblem 2

Set the factor '(3 + 5c)' equal to zero and attempt to solve: Simplifying 3 + 5c = 0 Solving 3 + 5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + 5c = 0 + -3 Combine like terms: 3 + -3 = 0 0 + 5c = 0 + -3 5c = 0 + -3 Combine like terms: 0 + -3 = -3 5c = -3 Divide each side by '5'. c = -0.6 Simplifying c = -0.6

Solution

c = {-9, -0.6}

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