(5c+3)-6c=7(2c+3)

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Solution for (5c+3)-6c=7(2c+3) equation: 



(5c+3)-6c=7(2c+3)

We move all terms to the left:

(5c+3)-6c-(7(2c+3))=0

We add all the numbers together, and all the variables

-6c+(5c+3)-(7(2c+3))=0

We get rid of parentheses

-6c+5c-(7(2c+3))+3=0



We calculate terms in parentheses: -(7(2c+3)), so:

7(2c+3)

We multiply parentheses

14c+21

Back to the equation:

-(14c+21)



We add all the numbers together, and all the variables

-1c-(14c+21)+3=0

We get rid of parentheses

-1c-14c-21+3=0

We add all the numbers together, and all the variables

-15c-18=0

We move all terms containing c to the left, all other terms to the right

-15c=18

c=18/-15

c=-1+1/5

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