(5c-1)(c-2)=0

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Solution for (5c-1)(c-2)=0 equation:


Simplifying
(5c + -1)(c + -2) = 0

Reorder the terms:
(-1 + 5c)(c + -2) = 0

Reorder the terms:
(-1 + 5c)(-2 + c) = 0

Multiply (-1 + 5c) * (-2 + c)
(-1(-2 + c) + 5c * (-2 + c)) = 0
((-2 * -1 + c * -1) + 5c * (-2 + c)) = 0
((2 + -1c) + 5c * (-2 + c)) = 0
(2 + -1c + (-2 * 5c + c * 5c)) = 0
(2 + -1c + (-10c + 5c2)) = 0

Combine like terms: -1c + -10c = -11c
(2 + -11c + 5c2) = 0

Solving
2 + -11c + 5c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(1 + -5c)(2 + -1c) = 0

Subproblem 1

Set the factor '(1 + -5c)' equal to zero and attempt to solve: Simplifying 1 + -5c = 0 Solving 1 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -5c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -5c = 0 + -1 -5c = 0 + -1 Combine like terms: 0 + -1 = -1 -5c = -1 Divide each side by '-5'. c = 0.2 Simplifying c = 0.2

Subproblem 2

Set the factor '(2 + -1c)' equal to zero and attempt to solve: Simplifying 2 + -1c = 0 Solving 2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1c = 0 + -2 -1c = 0 + -2 Combine like terms: 0 + -2 = -2 -1c = -2 Divide each side by '-1'. c = 2 Simplifying c = 2

Solution

c = {0.2, 2}

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