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(5c-3)/(c-5)=0
Domain of the equation: (c-5)!=0We multiply all the terms by the denominator
We move all terms containing c to the left, all other terms to the right
c!=5
c∈R
(5c-3)=0
We get rid of parentheses
5c-3=0
We move all terms containing c to the left, all other terms to the right
5c=3
c=3/5
c=3/5
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