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(5d+4)(2d+9)=0
We multiply parentheses ..
(+10d^2+45d+8d+36)=0
We get rid of parentheses
10d^2+45d+8d+36=0
We add all the numbers together, and all the variables
10d^2+53d+36=0
a = 10; b = 53; c = +36;
Δ = b2-4ac
Δ = 532-4·10·36
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(53)-37}{2*10}=\frac{-90}{20} =-4+1/2 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(53)+37}{2*10}=\frac{-16}{20} =-4/5 $
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