(5d+8)+(10d-3)=(10d+11)

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Solution for (5d+8)+(10d-3)=(10d+11) equation: 



(5d+8)+(10d-3)=(10d+11)

We move all terms to the left:

(5d+8)+(10d-3)-((10d+11))=0

We get rid of parentheses

5d+10d-((10d+11))+8-3=0



We calculate terms in parentheses: -((10d+11)), so:

(10d+11)

We get rid of parentheses

10d+11

Back to the equation:

-(10d+11)



We add all the numbers together, and all the variables

15d-(10d+11)+5=0

We get rid of parentheses

15d-10d-11+5=0

We add all the numbers together, and all the variables

5d-6=0

We move all terms containing d to the left, all other terms to the right

5d=6

d=6/5

d=1+1/5

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