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(5d-5)(d+11)=0
We multiply parentheses ..
(+5d^2+55d-5d-55)=0
We get rid of parentheses
5d^2+55d-5d-55=0
We add all the numbers together, and all the variables
5d^2+50d-55=0
a = 5; b = 50; c = -55;
Δ = b2-4ac
Δ = 502-4·5·(-55)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-60}{2*5}=\frac{-110}{10} =-11 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+60}{2*5}=\frac{10}{10} =1 $
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