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(5e+6)(9e)=90
We move all terms to the left:
(5e+6)(9e)-(90)=0
We multiply parentheses
45e^2+54e-90=0
a = 45; b = 54; c = -90;
Δ = b2-4ac
Δ = 542-4·45·(-90)
Δ = 19116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{19116}=\sqrt{324*59}=\sqrt{324}*\sqrt{59}=18\sqrt{59}$$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-18\sqrt{59}}{2*45}=\frac{-54-18\sqrt{59}}{90} $$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+18\sqrt{59}}{2*45}=\frac{-54+18\sqrt{59}}{90} $
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