(5f-11)=28

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Solution for (5f-11)=28 equation: 



(5f-11)=28

We move all terms to the left:

(5f-11)-(28)=0

We get rid of parentheses

5f-11-28=0

We add all the numbers together, and all the variables

5f-39=0

We move all terms containing f to the left, all other terms to the right

5f=39

f=39/5

f=7+4/5

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