(5f-7)=+(2f-2)

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Solution for (5f-7)=+(2f-2) equation: 



(5f-7)=+(2f-2)

We move all terms to the left:

(5f-7)-(+(2f-2))=0

We get rid of parentheses

5f-(+(2f-2))-7=0



We calculate terms in parentheses: -(+(2f-2)), so:

+(2f-2)

determiningTheFunctionDomain
(2f-2)

We get rid of parentheses

2f-2

Back to the equation:

-(2f-2)



We get rid of parentheses

5f-2f+2-7=0

We add all the numbers together, and all the variables

3f-5=0

We move all terms containing f to the left, all other terms to the right

3f=5

f=5/3

f=1+2/3

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