(5h+1)/3=(h-4)/55

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Solution for (5h+1)/3=(h-4)/55 equation: 



(5h+1)/3=(h-4)/55

We move all terms to the left:

(5h+1)/3-((h-4)/55)=0

We calculate fractions


5h/()+(-((h-4)*3)/()=0



We calculate terms in parentheses: +(-((h-4)*3)/(), so:

-((h-4)*3)/(

We multiply all the terms by the denominator


-((h-4)*3)



We calculate terms in parentheses: -((h-4)*3), so:

(h-4)*3

We multiply parentheses

3h-12

Back to the equation:

-(3h-12)



We get rid of parentheses

-3h+12

Back to the equation:

+(-3h+12)



We get rid of parentheses

5h/()-3h+12=0

We multiply all the terms by the denominator


5h-3h*()+12*()=0

We add all the numbers together, and all the variables

5h-3h*()=0

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