(5i)(i)(-2i)=0

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Solution for (5i)(i)(-2i)=0 equation: 



(5i)(i)(-2i)=0

We multiply parentheses

-10i^2=0

a = -10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-10)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{0}{-20}=0$

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