(5j-3)=(10j-2)

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Solution for (5j-3)=(10j-2) equation: 



(5j-3)=(10j-2)

We move all terms to the left:

(5j-3)-((10j-2))=0

We get rid of parentheses

5j-((10j-2))-3=0



We calculate terms in parentheses: -((10j-2)), so:

(10j-2)

We get rid of parentheses

10j-2

Back to the equation:

-(10j-2)



We get rid of parentheses

5j-10j+2-3=0

We add all the numbers together, and all the variables

-5j-1=0

We move all terms containing j to the left, all other terms to the right

-5j=1

j=1/-5

j=-1/5

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