(5m-2)(m=3)

Solution for (5m-2)(m=3) equation:

(5m-2)(m=3)

We move all terms to the left:

(5m-2)(m-(3))=0

We multiply parentheses ..

(+5m^2-15m-2m+6)=0

We get rid of parentheses

5m^2-15m-2m+6=0

We add all the numbers together, and all the variables

5m^2-17m+6=0

a = 5; b = -17; c = +6;
Δ = b2-4ac
Δ = -172-4·5·6
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-13}{2*5}=\frac{4}{10}
=2/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+13}{2*5}=\frac{30}{10}
=3
$