(5m-6)(2m+1)=0

Solution for (5m-6)(2m+1)=0 equation:

(5m-6)(2m+1)=0

We multiply parentheses ..

(+10m^2+5m-12m-6)=0

We get rid of parentheses

10m^2+5m-12m-6=0

We add all the numbers together, and all the variables

10m^2-7m-6=0

a = 10; b = -7; c = -6;
Δ = b2-4ac
Δ = -72-4·10·(-6)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-17}{2*10}=\frac{-10}{20}
=-1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+17}{2*10}=\frac{24}{20}
=1+1/5
$