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(5m-8)(5m+7)=0
We multiply parentheses ..
(+25m^2+35m-40m-56)=0
We get rid of parentheses
25m^2+35m-40m-56=0
We add all the numbers together, and all the variables
25m^2-5m-56=0
a = 25; b = -5; c = -56;
Δ = b2-4ac
Δ = -52-4·25·(-56)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5625}=75$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-75}{2*25}=\frac{-70}{50} =-1+2/5 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+75}{2*25}=\frac{80}{50} =1+3/5 $
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