(5m-8)(m-8)=0

Solution for (5m-8)(m-8)=0 equation:

(5m-8)(m-8)=0

We multiply parentheses ..

(+5m^2-40m-8m+64)=0

We get rid of parentheses

5m^2-40m-8m+64=0

We add all the numbers together, and all the variables

5m^2-48m+64=0

a = 5; b = -48; c = +64;
Δ = b2-4ac
Δ = -482-4·5·64
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-32}{2*5}=\frac{16}{10}
=1+3/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+32}{2*5}=\frac{80}{10}
=8
$