(5n/4)n+2=22n-22

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Solution for (5n/4)n+2=22n-22 equation: 


n in (-oo:+oo)

((5*n)/4)*n+2 = 22*n-22 // - 22*n-22

((5*n)/4)*n-(22*n)+2+22 = 0

((5*n)/4)*n-22*n+2+22 = 0

5/4*n^2-22*n+24 = 0

DELTA = (-22)^2-(5/4*4*24)

DELTA = 364

DELTA > 0

n = (364^(1/2)+22)/(5/4*2) or n = (22-364^(1/2))/(5/4*2)

n = 2/5*(2*91^(1/2)+22) or n = 2/5*(22-2*91^(1/2))

n in { 2/5*(22-2*91^(1/2)), 2/5*(2*91^(1/2)+22) }

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