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(5p-12)(6p+8)=0
We multiply parentheses ..
(+30p^2+40p-72p-96)=0
We get rid of parentheses
30p^2+40p-72p-96=0
We add all the numbers together, and all the variables
30p^2-32p-96=0
a = 30; b = -32; c = -96;
Δ = b2-4ac
Δ = -322-4·30·(-96)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12544}=112$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-112}{2*30}=\frac{-80}{60} =-1+1/3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+112}{2*30}=\frac{144}{60} =2+2/5 $
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