(5p-4)/6)-(2p+3)/2)=7

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Solution for (5p-4)/6)-(2p+3)/2)=7 equation: 



(5p-4)/6)-(2p+3)/2)=7

We move all terms to the left:

(5p-4)/6)-(2p+3)/2)-(7)=0



Domain of the equation: 6)-(2p!=0

p∈R



We calculate fractions


((5p-4)*2)-7)/4p^2+3*6)-2p/4p^2=0



We calculate terms in parentheses: +((5p-4)*2), so:

(5p-4)*2

We multiply parentheses

10p-8

Back to the equation:

+(10p-8)



We can not solve this equation

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