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(5r+20)=(4r-2)
We move all terms to the left:
(5r+20)-((4r-2))=0
We get rid of parentheses
5r-((4r-2))+20=0
We calculate terms in parentheses: -((4r-2)), so:We get rid of parentheses
(4r-2)
We get rid of parentheses
4r-2
Back to the equation:
-(4r-2)
5r-4r+2+20=0
We add all the numbers together, and all the variables
r+22=0
We move all terms containing r to the left, all other terms to the right
r=-22
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