(5r+3)r+1=0

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Solution for (5r+3)r+1=0 equation: 



(5r+3)r+1=0

We multiply parentheses

5r^2+3r+1=0

a = 5; b = 3; c = +1;
Δ = b2-4ac
Δ = 32-4·5·1
Δ = -11
Delta is less than zero, so there is no solution for the equation

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