(5t+1)+6=3(4+m)+(2m-1)

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Solution for (5t+1)+6=3(4+m)+(2m-1) equation:


Simplifying
(5t + 1) + 6 = 3(4 + m) + (2m + -1)

Reorder the terms:
(1 + 5t) + 6 = 3(4 + m) + (2m + -1)

Remove parenthesis around (1 + 5t)
1 + 5t + 6 = 3(4 + m) + (2m + -1)

Reorder the terms:
1 + 6 + 5t = 3(4 + m) + (2m + -1)

Combine like terms: 1 + 6 = 7
7 + 5t = 3(4 + m) + (2m + -1)
7 + 5t = (4 * 3 + m * 3) + (2m + -1)
7 + 5t = (12 + 3m) + (2m + -1)

Reorder the terms:
7 + 5t = 12 + 3m + (-1 + 2m)

Remove parenthesis around (-1 + 2m)
7 + 5t = 12 + 3m + -1 + 2m

Reorder the terms:
7 + 5t = 12 + -1 + 3m + 2m

Combine like terms: 12 + -1 = 11
7 + 5t = 11 + 3m + 2m

Combine like terms: 3m + 2m = 5m
7 + 5t = 11 + 5m

Solving
7 + 5t = 11 + 5m

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 5t = 11 + -7 + 5m

Combine like terms: 7 + -7 = 0
0 + 5t = 11 + -7 + 5m
5t = 11 + -7 + 5m

Combine like terms: 11 + -7 = 4
5t = 4 + 5m

Divide each side by '5'.
t = 0.8 + m

Simplifying
t = 0.8 + m

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