(5t+4)(2t+1)=

Solution for (5t+4)(2t+1)= equation:

Simplifying
(5t + 4)(2t + 1) = 0

Reorder the terms:
(4 + 5t)(2t + 1) = 0

Reorder the terms:
(4 + 5t)(1 + 2t) = 0

Multiply (4 + 5t) * (1 + 2t)
(4(1 + 2t) + 5t * (1 + 2t)) = 0
((1 * 4 + 2t * 4) + 5t * (1 + 2t)) = 0
((4 + 8t) + 5t * (1 + 2t)) = 0
(4 + 8t + (1 * 5t + 2t * 5t)) = 0
(4 + 8t + (5t + 10t2)) = 0

Combine like terms: 8t + 5t = 13t
(4 + 13t + 10t2) = 0

Solving
4 + 13t + 10t2 = 0

Solving for variable 't'.

Factor a trinomial.
(4 + 5t)(1 + 2t) = 0

Subproblem 1
Set the factor '(4 + 5t)' equal to zero and attempt to solve:

Simplifying
4 + 5t = 0

Solving
4 + 5t = 0

Move all terms containing t to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 5t = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 5t = 0 + -4
5t = 0 + -4

Combine like terms: 0 + -4 = -4
5t = -4

Divide each side by '5'.
t = -0.8

Simplifying
t = -0.8
Subproblem 2
Set the factor '(1 + 2t)' equal to zero and attempt to solve:

Simplifying
1 + 2t = 0

Solving
1 + 2t = 0

Move all terms containing t to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2t = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2t = 0 + -1
2t = 0 + -1

Combine like terms: 0 + -1 = -1
2t = -1

Divide each side by '2'.
t = -0.5

Simplifying
t = -0.5
Solution
t = {-0.8, -0.5}