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(5t-6)=2(1t+1)+2
We move all terms to the left:
(5t-6)-(2(1t+1)+2)=0
We add all the numbers together, and all the variables
(5t-6)-(2(t+1)+2)=0
We get rid of parentheses
5t-(2(t+1)+2)-6=0
We calculate terms in parentheses: -(2(t+1)+2), so:We get rid of parentheses
2(t+1)+2
We multiply parentheses
2t+2+2
We add all the numbers together, and all the variables
2t+4
Back to the equation:
-(2t+4)
5t-2t-4-6=0
We add all the numbers together, and all the variables
3t-10=0
We move all terms containing t to the left, all other terms to the right
3t=10
t=10/3
t=3+1/3
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