(5u+1)(2+u)=0

Solution for (5u+1)(2+u)=0 equation:

(5u+1)(2+u)=0

We add all the numbers together, and all the variables

(5u+1)(u+2)=0

We multiply parentheses ..

(+5u^2+10u+u+2)=0

We get rid of parentheses

5u^2+10u+u+2=0

We add all the numbers together, and all the variables

5u^2+11u+2=0

a = 5; b = 11; c = +2;
Δ = b2-4ac
Δ = 112-4·5·2
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-9}{2*5}=\frac{-20}{10}
=-2
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+9}{2*5}=\frac{-2}{10}
=-1/5
$