(5u+1)(6-u)=0

Solution for (5u+1)(6-u)=0 equation:

(5u+1)(6-u)=0

We add all the numbers together, and all the variables

(5u+1)(-1u+6)=0

We multiply parentheses ..

(-5u^2+30u-1u+6)=0

We get rid of parentheses

-5u^2+30u-1u+6=0

We add all the numbers together, and all the variables

-5u^2+29u+6=0

a = -5; b = 29; c = +6;
Δ = b2-4ac
Δ = 292-4·(-5)·6
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-31}{2*-5}=\frac{-60}{-10}
=+6
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+31}{2*-5}=\frac{2}{-10}
=-1/5
$