(5u+1)/3=(7u+2)/(6)+4

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Solution for (5u+1)/3=(7u+2)/(6)+4 equation: 


u in (-oo:+oo)

(5*u+1)/3 = (7*u+2)/6+4 // - (7*u+2)/6+4

(5*u+1)/3-((7*u+2)/6)-4 = 0

(5*u+1)/3+(-1*(7*u+2))/6-4 = 0

(6*(5*u+1))/(3*6)+(-1*3*(7*u+2))/(3*6)+(-4*3*6)/(3*6) = 0

6*(5*u+1)-1*3*(7*u+2)-4*3*6 = 0

9*u-72 = 0

(9*u-72)/(3*6) = 0

(9*u-72)/(3*6) = 0 // * 3*6

9*u-72 = 0

9*u-72 = 0 // + 72

9*u = 72 // : 9

u = 72/9

u = 8

u = 8

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