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(5u+2)(4-u)=0
We add all the numbers together, and all the variables
(5u+2)(-1u+4)=0
We multiply parentheses ..
(-5u^2+20u-2u+8)=0
We get rid of parentheses
-5u^2+20u-2u+8=0
We add all the numbers together, and all the variables
-5u^2+18u+8=0
a = -5; b = 18; c = +8;
Δ = b2-4ac
Δ = 182-4·(-5)·8
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-22}{2*-5}=\frac{-40}{-10} =+4 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+22}{2*-5}=\frac{4}{-10} =-2/5 $
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