(5u+8)(4-u)=0

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Solution for (5u+8)(4-u)=0 equation:



(5u+8)(4-u)=0
We add all the numbers together, and all the variables
(5u+8)(-1u+4)=0
We multiply parentheses ..
(-5u^2+20u-8u+32)=0
We get rid of parentheses
-5u^2+20u-8u+32=0
We add all the numbers together, and all the variables
-5u^2+12u+32=0
a = -5; b = 12; c = +32;
Δ = b2-4ac
Δ = 122-4·(-5)·32
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-28}{2*-5}=\frac{-40}{-10} =+4 $
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+28}{2*-5}=\frac{16}{-10} =-1+3/5 $

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