(5u-6/3)=(7u-9/6)+2

Solution for (5u-6/3)=(7u-9/6)+2 equation:

(5u-6/3)=(7u-9/6)+2

We move all terms to the left:

(5u-6/3)-((7u-9/6)+2)=0

We add all the numbers together, and all the variables

(5u-2)-((+7u-9/6)+2)=0

We get rid of parentheses

5u-((+7u-9/6)+2)-2=0

We multiply all the terms by the denominator


5u*6)+2)-((+7u-9-2*6)+2)=0

We add all the numbers together, and all the variables

5u*6)+2)-((7u-21)+2)=0

We add all the numbers together, and all the variables

5u*6)+2)-((7u=0

Wy multiply elements

30u^2=0

a = 30; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·30·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$u=\frac{-b}{2a}=\frac{0}{60}=0$