(5u-6/3)=(u-3/2)+10

Solution for (5u-6/3)=(u-3/2)+10 equation:

(5u-6/3)=(u-3/2)+10

We move all terms to the left:

(5u-6/3)-((u-3/2)+10)=0

We add all the numbers together, and all the variables

(5u-2)-((+u-3/2)+10)=0

We get rid of parentheses

5u-((+u-3/2)+10)-2=0

We multiply all the terms by the denominator


5u*2)+10)-((+u-3-2*2)+10)=0

We add all the numbers together, and all the variables

5u*2)+10)-((u-7)+10)=0

We add all the numbers together, and all the variables

5u*2)+10)-((u=0

Wy multiply elements

10u^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$u=\frac{-b}{2a}=\frac{0}{20}=0$