(5v+2)(1+v)=0

Solution for (5v+2)(1+v)=0 equation:

Simplifying
(5v + 2)(1 + v) = 0

Reorder the terms:
(2 + 5v)(1 + v) = 0

Multiply (2 + 5v) * (1 + v)
(2(1 + v) + 5v * (1 + v)) = 0
((1 * 2 + v * 2) + 5v * (1 + v)) = 0
((2 + 2v) + 5v * (1 + v)) = 0
(2 + 2v + (1 * 5v + v * 5v)) = 0
(2 + 2v + (5v + 5v2)) = 0

Combine like terms: 2v + 5v = 7v
(2 + 7v + 5v2) = 0

Solving
2 + 7v + 5v2 = 0

Solving for variable 'v'.

Factor a trinomial.
(1 + v)(2 + 5v) = 0

Subproblem 1
Set the factor '(1 + v)' equal to zero and attempt to solve:

Simplifying
1 + v = 0

Solving
1 + v = 0

Move all terms containing v to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + v = 0 + -1

Combine like terms: 1 + -1 = 0
0 + v = 0 + -1
v = 0 + -1

Combine like terms: 0 + -1 = -1
v = -1

Simplifying
v = -1
Subproblem 2
Set the factor '(2 + 5v)' equal to zero and attempt to solve:

Simplifying
2 + 5v = 0

Solving
2 + 5v = 0

Move all terms containing v to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 5v = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 5v = 0 + -2
5v = 0 + -2

Combine like terms: 0 + -2 = -2
5v = -2

Divide each side by '5'.
v = -0.4

Simplifying
v = -0.4
Solution
v = {-1, -0.4}