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(5v+2)(8-v)=0
We add all the numbers together, and all the variables
(5v+2)(-1v+8)=0
We multiply parentheses ..
(-5v^2+40v-2v+16)=0
We get rid of parentheses
-5v^2+40v-2v+16=0
We add all the numbers together, and all the variables
-5v^2+38v+16=0
a = -5; b = 38; c = +16;
Δ = b2-4ac
Δ = 382-4·(-5)·16
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-42}{2*-5}=\frac{-80}{-10} =+8 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+42}{2*-5}=\frac{4}{-10} =-2/5 $
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