(5v+8)(1-v)=0

Solution for (5v+8)(1-v)=0 equation:

(5v+8)(1-v)=0

We add all the numbers together, and all the variables

(5v+8)(-1v+1)=0

We multiply parentheses ..

(-5v^2+5v-8v+8)=0

We get rid of parentheses

-5v^2+5v-8v+8=0

We add all the numbers together, and all the variables

-5v^2-3v+8=0

a = -5; b = -3; c = +8;
Δ = b2-4ac
Δ = -32-4·(-5)·8
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-13}{2*-5}=\frac{-10}{-10}
=1
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+13}{2*-5}=\frac{16}{-10}
=-1+3/5
$