(5v-1)(5-v)=0

Solution for (5v-1)(5-v)=0 equation:

(5v-1)(5-v)=0

We add all the numbers together, and all the variables

(5v-1)(-1v+5)=0

We multiply parentheses ..

(-5v^2+25v+v-5)=0

We get rid of parentheses

-5v^2+25v+v-5=0

We add all the numbers together, and all the variables

-5v^2+26v-5=0

a = -5; b = 26; c = -5;
Δ = b2-4ac
Δ = 262-4·(-5)·(-5)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-24}{2*-5}=\frac{-50}{-10}
=+5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+24}{2*-5}=\frac{-2}{-10}
=1/5
$