(5v-4u)(5v+4u)=

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Solution for (5v-4u)(5v+4u)= equation: 


Simplifying
(5v + -4u)(5v + 4u) = 0

Reorder the terms:
(-4u + 5v)(5v + 4u) = 0

Reorder the terms:
(-4u + 5v)(4u + 5v) = 0

Multiply (-4u + 5v) * (4u + 5v)
(-4u * (4u + 5v) + 5v * (4u + 5v)) = 0
((4u * -4u + 5v * -4u) + 5v * (4u + 5v)) = 0

Reorder the terms:
((-20uv + -16u2) + 5v * (4u + 5v)) = 0
((-20uv + -16u2) + 5v * (4u + 5v)) = 0
(-20uv + -16u2 + (4u * 5v + 5v * 5v)) = 0
(-20uv + -16u2 + (20uv + 25v2)) = 0

Reorder the terms:
(-20uv + 20uv + -16u2 + 25v2) = 0

Combine like terms: -20uv + 20uv = 0
(0 + -16u2 + 25v2) = 0
(-16u2 + 25v2) = 0

Solving
-16u2 + 25v2 = 0

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '-25v2' to each side of the equation.
-16u2 + 25v2 + -25v2 = 0 + -25v2

Combine like terms: 25v2 + -25v2 = 0
-16u2 + 0 = 0 + -25v2
-16u2 = 0 + -25v2
Remove the zero:
-16u2 = -25v2

Divide each side by '-16'.
u2 = 1.5625v2

Simplifying
u2 = 1.5625v2

Take the square root of each side:
u = {-1.25v, 1.25v}

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