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(5v-8)(5-v)=0
We add all the numbers together, and all the variables
(5v-8)(-1v+5)=0
We multiply parentheses ..
(-5v^2+25v+8v-40)=0
We get rid of parentheses
-5v^2+25v+8v-40=0
We add all the numbers together, and all the variables
-5v^2+33v-40=0
a = -5; b = 33; c = -40;
Δ = b2-4ac
Δ = 332-4·(-5)·(-40)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-17}{2*-5}=\frac{-50}{-10} =+5 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+17}{2*-5}=\frac{-16}{-10} =1+3/5 $
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