(5w+1)(3-w)=0

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Solution for (5w+1)(3-w)=0 equation:



(5w+1)(3-w)=0
We add all the numbers together, and all the variables
(5w+1)(-1w+3)=0
We multiply parentheses ..
(-5w^2+15w-1w+3)=0
We get rid of parentheses
-5w^2+15w-1w+3=0
We add all the numbers together, and all the variables
-5w^2+14w+3=0
a = -5; b = 14; c = +3;
Δ = b2-4ac
Δ = 142-4·(-5)·3
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-16}{2*-5}=\frac{-30}{-10} =+3 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+16}{2*-5}=\frac{2}{-10} =-1/5 $

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