(5w+1)(3-w)=0

Solution for (5w+1)(3-w)=0 equation:

(5w+1)(3-w)=0

We add all the numbers together, and all the variables

(5w+1)(-1w+3)=0

We multiply parentheses ..

(-5w^2+15w-1w+3)=0

We get rid of parentheses

-5w^2+15w-1w+3=0

We add all the numbers together, and all the variables

-5w^2+14w+3=0

a = -5; b = 14; c = +3;
Δ = b2-4ac
Δ = 142-4·(-5)·3
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-16}{2*-5}=\frac{-30}{-10}
=+3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+16}{2*-5}=\frac{2}{-10}
=-1/5
$