(5w+2)(1+w)=0

Solution for (5w+2)(1+w)=0 equation:

(5w+2)(1+w)=0

We add all the numbers together, and all the variables

(5w+2)(w+1)=0

We multiply parentheses ..

(+5w^2+5w+2w+2)=0

We get rid of parentheses

5w^2+5w+2w+2=0

We add all the numbers together, and all the variables

5w^2+7w+2=0

a = 5; b = 7; c = +2;
Δ = b2-4ac
Δ = 72-4·5·2
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-3}{2*5}=\frac{-10}{10}
=-1
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+3}{2*5}=\frac{-4}{10}
=-2/5
$