(5w+2)(1-w)=0

Solution for (5w+2)(1-w)=0 equation:

(5w+2)(1-w)=0

We add all the numbers together, and all the variables

(5w+2)(-1w+1)=0

We multiply parentheses ..

(-5w^2+5w-2w+2)=0

We get rid of parentheses

-5w^2+5w-2w+2=0

We add all the numbers together, and all the variables

-5w^2+3w+2=0

a = -5; b = 3; c = +2;
Δ = b2-4ac
Δ = 32-4·(-5)·2
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-7}{2*-5}=\frac{-10}{-10}
=1
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+7}{2*-5}=\frac{4}{-10}
=-2/5
$