(5w+2)(3-w)=0

Solution for (5w+2)(3-w)=0 equation:

(5w+2)(3-w)=0

We add all the numbers together, and all the variables

(5w+2)(-1w+3)=0

We multiply parentheses ..

(-5w^2+15w-2w+6)=0

We get rid of parentheses

-5w^2+15w-2w+6=0

We add all the numbers together, and all the variables

-5w^2+13w+6=0

a = -5; b = 13; c = +6;
Δ = b2-4ac
Δ = 132-4·(-5)·6
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-17}{2*-5}=\frac{-30}{-10}
=+3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+17}{2*-5}=\frac{4}{-10}
=-2/5
$