(5w+3)(2w-6)=0

Solution for (5w+3)(2w-6)=0 equation:

(5w+3)(2w-6)=0

We multiply parentheses ..

(+10w^2-30w+6w-18)=0

We get rid of parentheses

10w^2-30w+6w-18=0

We add all the numbers together, and all the variables

10w^2-24w-18=0

a = 10; b = -24; c = -18;
Δ = b2-4ac
Δ = -242-4·10·(-18)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-36}{2*10}=\frac{-12}{20}
=-3/5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+36}{2*10}=\frac{60}{20}
=3
$