(5w+6)(2-w)=0

Solution for (5w+6)(2-w)=0 equation:

(5w+6)(2-w)=0

We add all the numbers together, and all the variables

(5w+6)(-1w+2)=0

We multiply parentheses ..

(-5w^2+10w-6w+12)=0

We get rid of parentheses

-5w^2+10w-6w+12=0

We add all the numbers together, and all the variables

-5w^2+4w+12=0

a = -5; b = 4; c = +12;
Δ = b2-4ac
Δ = 42-4·(-5)·12
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-16}{2*-5}=\frac{-20}{-10}
=+2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+16}{2*-5}=\frac{12}{-10}
=-1+1/5
$