(5w+9)(1+w)=0

Solution for (5w+9)(1+w)=0 equation:

(5w+9)(1+w)=0

We add all the numbers together, and all the variables

(5w+9)(w+1)=0

We multiply parentheses ..

(+5w^2+5w+9w+9)=0

We get rid of parentheses

5w^2+5w+9w+9=0

We add all the numbers together, and all the variables

5w^2+14w+9=0

a = 5; b = 14; c = +9;
Δ = b2-4ac
Δ = 142-4·5·9
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-4}{2*5}=\frac{-18}{10}
=-1+4/5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+4}{2*5}=\frac{-10}{10}
=-1
$