(5w+w)(5w+1)=0

Solution for (5w+w)(5w+1)=0 equation:

(5w+w)(5w+1)=0

We add all the numbers together, and all the variables

(+6w)(5w+1)=0

We multiply parentheses ..

(+30w^2+6w)=0

We get rid of parentheses

30w^2+6w=0

a = 30; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·30·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*30}=\frac{-12}{60}
=-1/5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*30}=\frac{0}{60}
=0
$